projectile, large, is located in seaaims and objectives lab report

Topic 9 of 11. A cannon, located 60.0m from the base of a vertical 25.0m tall cliff, shoots a 15 kg shell at 43.0degrees above the horizontal toward the cliff. (b) Find the speed and direction of the stone just before it hits the ground? max range at 45, equal ranges for launch angles that exceed and fall short of 45 by equal amounts (ex. The magnitude of the components of displacement along these axes are and . The following are all projectile motion equations in vertical and horizontal directions. Look for more clues & answers (a) The time the berry reaches the ground. Determine the time of flight of the projectile. The path that the object follows is called its trajectory. Notched Projectile Points of the East Central Region. Since these devices are acted upon by the lift of wings and the thrust of engines in addition to the force of gravity, they are not really projectiles. Projectile from lake is found in sea (9) Free pack of tutorial cryptic crosswords so you can learn step-by-step. A tossed helium-filled balloon is not normally considered a projectile as the drag and buoyant forces on it are as significant as the weight. Projectile motion is the motion of an object thrown or projected into the air, subject to only the acceleration of gravity. xo b. The projectile is the object while the path taken by the projectile is known as a trajectory. Click the answer to find similar crossword clues . Find the following: T tof = 2(v0sin) g. Let your mind carry you away while seeing it rotate, round and round, at perfect balance. Below are all possible answers to this clue ordered by its rank. How many solutions does Projectile, Large, Is Located In Sea have? Projectile.getLocation returns it's initial point in 3D space (AKA where it spawned).. Global farm commodities trader Cargill Inc (CARG.UL) said on Thursday that an ocean vessel it chartered was "hit by a projectile" on the Black Sea, but that the ship remained seaworthy and all . Add to Cart | Add to Compare; Republic Fleet Depleted Uranium L (projectile ammo) 100,000 units. Elko Eared. The projectile strikes the ground after time at horizontal distance from the base of the platform. (b) When the vertical component of projectiles velocity is zero i.e. At this point our general projectile ceases to be an object with a launch point and a landing point and it starts being a satellite, permanently circling the Earth, perpetually changing direction and thus accelerating under the influence of gravity, but never landing anywhere. Crossword Clue, American Artist (With A Famous Mother), D. 1903 Crossword Clue, Pre Programme Car, 50% Less Consumed Crossword Clue, What "Pi Times The Radius Squared" Measures Crossword Clue, The Red Cross, E.G., Briefly Crossword Clue, They Might Put You To Sleep Crossword Clue, Text Usually Answered With A Time Crossword Clue, Member of the clergy I located in large church, Sea creature, first in particular place, not large. Find: Author: Dr. Ali Nemati. A stone is thrown horizontally into the air with a speed of $8\,{\rm m/s}$ from the top of a $20\,{\rm m}$-high cliff and hits the ground. \[\begin{aligned} \Delta x &= R=v_{0x} t_T \\ \\ 13.8 &= v_{0x} (1.40)\\ \\ \Rightarrow v_{0x} &=\frac{13.8}{1.4}=9.85\,{\rm m/s} \end{aligned}\] In this part $v_{0y}$ is unknown. And those are only events of last few years. In other words, any motion in two dimensions and only under the effect of gravitational force is called projectile motion. A projectile and a satellite are both governed by the same physical principles even though they have different names. Last Modified: 8/25/2020 In this part, $v_{0x}$ is requested so The object is called a projectile, and its path is called its trajectory. $3.75. For projectile motion we have x = v cos t, y = v sin t - gt 2. A projectile is fired at time t = 0.0 s, from point 0 at the edge of a cliff, with initial velocity components of V ax= 50m/s and V ay= 200m/s. As expected, the vertical component has a minus sign indicates that the projectile direction is down. The cliff is 30 m high, and the projectile is launched from the cliff in the direction of the level plane below. Here are the possible solutions for "Projectile, originally lost, is in the sea" clue. Setting $v_y=0$, one can get the time between the initial time and where the projectile reaches the highest point. Try to find some letters, so you can find your solution more easily. In this article we have shared the answer for Large projectile used by the armies of the sea. what is the most populous city located on an island in the mediterranean sea? For now, let the angle the projectile is fired at be theta Begin by finding the time the projectile is in the air for. \[\begin{aligned} \text{Displacement}&:\,\Delta x=\underbrace{\left(v_0 \cos \theta\right)}_{v_{0x}}t\\ \text{Velocity}&:\, v_x=v_0 \cos \theta \end{aligned}\], \[\begin{aligned} \text{Displacement}&:\, \Delta y=\frac 12 (-g)t^2 +(\underbrace{v_0 \sin \theta}_{v_{0y}})\,t\\ \text{Velocity I}&:\, v_y = \underbrace{v_0 \sin \theta}_{v_{0y}}+(-g)t \\ \text{Velocity II}&:\, v_y^2 -\left(v_0 \sin \theta\right)^2=2(-g)\Delta y \end{aligned}\], \[\begin{aligned} \theta &= \tan^{-1} \left(\frac{v_y}{v_x}\right)\\ &=\tan^{-1} \left(\frac{v_0 \sin \theta -gt}{v_0 \cos \theta}\right) \end{aligned}\], \[ y(x)=x\:\tan \theta-\frac{gx^2}{2v_0^2\,\cos^2 \theta}\]. You didn't found your solution? Known: $\theta=35^\circ$, Range of projectile $R=13.8\,{\rm m}$, Maximum height $H=2.42\,{\rm m}$. Type of hotel which is located high above sea level and offer unobstructed panoramic views of the sea is known as hotels, Projectile, originally lost, is in the sea, Sea where the Greek island of Santorini is located, Sea in which the island of Cozumel is located, Country where the Mamara Sea is located. (c) To find the velocity of a projectile at any time, we require to compute its components at any instant of time. The only relevant quantities that might vary from projectile to projectile then are initial velocity and initial position, This is where we run into some linguistic complications. Since the berry hit the ground below the y-axis so the coordinate of impact is $(x=?,y=-h=-30)$, where $h$ is the vertical distance from the bird to the hitting point. Late to Transitional Archaic. The Early Paleoindian is characterized by Clovis and related projectile point forms. Our projectile motion calculator is a tool that helps you analyze the parabolic projectile motion. Of course, the pilot of a disabled airplane may regain control before crashing and avert disaster, but then the airplane wouldn't be a projectile anymore. If v is the initial velocity, g = acceleration due to gravity and H = maximum height in metres, = angle of the initial velocity from the horizontal plane (radians or degrees). The laws of physics are assumed universal until it can be demonstrated otherwise. Motion along the horizontal direction is uniform ($a_x=0$) and in vertical direction is free-fall motion ($a_y=-g$). We will try to find the right answer to this particular crossword clue. We provide the likeliest answers for every crossword clue. These axes are perpendicular, so Ax = A cos A x = A cos and Ay = A sin A y = A sin are used. An essential characteristic of a projectile is that its future has already been preordained. Summary. Large to Very Large: Middle Archaic: Valid Type: Big Sandy: Side Notch: Medium to Large: Early Archaic: Valid Type: Big Sandy Broad Base: Side Notch: Medium to Large . The time of flight of a projectile launched with initial vertical velocity v0y v 0 y on an even surface is given by. A projectile is launched horizontally at a speed of 40 meters per second from a platform located a vertical distance h above the ground. A projectile is launched at an angle of 14.00 above the horizontal: What is its initial speed if it hits a target that is located a horizontal distance of 160 m from the launch point and 14.0 m below the launch level? Even though the drag and buoyant forces acting on it are much greater in absolute terms than they are on the balloon, gravity is what really drives a crashing airplane. Fluted Cumberland Point Now there's fresh news of the USA betraying kurds and starting to openly steal oil reserves. Projectile Motion Problem -Diving off cliff Thread starter Chandasouk; Start date Oct 23, 2009; Oct 23, 2009 #1 Chandasouk. Objects traveling through what we call "outerspace" hardly seem like projectiles any more. If certain letters are known already, you can provide them in the form of a pattern: "CA????". So if something is launched off of a cliff, let's say, in this straight horizontal direction with no vertical component to start with, then it's a horizontally launched projectile. At the instant the berry is released it has a velocity of $10\,{\rm m/s}$ at an angle of $20^\circ$ from horizontal. Any object that is thrown into the air with an angle $\theta$ is projectile and its motion is called projectile motion. Word Craze is the best version of puzzle word games at the moment. Small to Medium. This level was last updated on November 29 2021 If you already solved these levels then turn back to the main page Word Craze Answers All Levels. The projectile is being reported to be an Intermediate Range Ballistic Missile . Enter the clue from your crossword in the first input box above. The Now substitute it into the horizontal distance formula to find the RANGE of Projectile as below \[\begin{aligned} \Delta x&=(v_0\,\cos \theta)\, t \\ &=(150\times \,\cos 37^\circ)(20.757) \\ &=(150\times 0.8)(20.757) \\ &=95.83\,{\rm m} \end{aligned}\], (b) One of the key features of projectile motions is that its vertical velocity, $v_y$, at the highest point of trajectory is zero. A projectile is fired at $150\,{\rm m/s}$ from a cliff with a height of $200\,{\rm m}$ at an angle of $37^\circ$ from horizontal. This is not to say that other forces do not exist, just that their effect is minimal in comparison. Bring the soothing comfort of precession, rotation, and peace of mind into your atmosphere. We found more than, 2020 - 2022 Copyright: For example. 3. vomiting, we tend to become truly miserable.. Vomiting is used by the body to rid of toxins or poisons you may have ingested. Problem (5): b) How long does it take to hit the ground? The projectile rises, then falls into the sea at point P. The time of flight of the projectile is 50.0s What is the y-coordinate of the projectile when its x-coordinate is 1000 m? The force of primary importance acting on a projectile is gravity. A type of large, side-notched points, found primarily in the southern portion of the North Coast Ranges and dated between ca. Refine the search results by specifying the number of letters. These axes are perpendicular, so and are used. In this short course, we illustrate the application of the projectile motion formulas by solving some simple examples. 40 & 50, 30 & 60, 0 & 90), Use the horizontal direction to determine the range as a function of time, Use the vertical direction to determine the time in the air, a baseball that has been pitched, batted, or thrown, a bullet the instant it exits the barrel of a gun or rifle, a moving airplane in the air with its engines and wings disabled, a runner in mid stride (since they momentarily lose contact with the ground), the space shuttle or any other spacecraft after main engine cut off (MECO). c) What is the initial horizontal velocity? Unit 2 of 9. (c) The velocity in the vertical direction begins to decrease as the . Notice how altitude affects this range. A projectile location system (10, 20, 30) includes a plurality of microphones (12, 13, 14) adapted to receive the acoustic wave generated by a projectile as it passes through a planar target region (11, 21, 39). Gravity isn't constant to begin with, but the variation is not noticeable over everyday ranges in altitude. Do this by considering the vertical component of velocity: s=0 total displacement when it falls is 0. u=37sintheta . The word ballistic has its origins in the Greek word (vallo), to throw, and surfaces repeatedly in the technical jargon of weaponry from ancient to modern times. Valid Type. [Neglect friction.] (d) With knowing the vertical and horizontal components of the projectiles velocity, we can find the resultant velocity vector bellow This covers the first five of the examples described at the beginning of this section (baseballs, bullets, buses in action-adventure movies, distressed airplanes, and joggers) but not the sixth (the space shuttle after MECO). d) With what velocity was the ball initially kicked ($\vec{v}$)? Enter the length or pattern for better results. Helium-filled balloons can't be thrown long distances and don't normally fall. The kinematic equations for a simple projectile are those of an object traveling with constant horizontal velocity and constant vertical acceleration. A projectile of mass 1 kg is launched from ground level toward the east at 200 m/s, at an angle of 6 to the horizontal. (b) The components of the velocity vector is determined as \[\begin{aligned}\text{Vertical component}: \, v_y&=(v_0 \sin \theta)-gt\\ &=(10\times \sin 20^\circ)-(9.8\times 2.848)\\ v_y&=-24.5\,{\rm m/s}\\ \text{Horizontal component}:\, v_x &=v_0\,\cos \theta \\ &=10\times \cos 20^\circ \\ v_x &=9.4\,{\rm m/s} \end{aligned}\] Thus, the vector addition of those components gets the velocity vector\[ \begin{aligned} \vec{v}&=v_x\,\hat{i} + v_y\,\hat{j}\\ &=9.4\,\hat{i} -24.5\,\hat{j} \end{aligned} \]. Homework Statement. 3-51. East Central Region . Maximum Projectile Range: Rifle. What effect would velocity have on range? crossword-solver.io, Linda And Paul Mc Cartney Album With A Sheep On The Cover Crossword Clue, Dope With European Camper Possibly Is Swiss Crossword Clue, Ceramic Iron Compound That's Nonconductive Crossword Clue, V. Alston (Landmark 2021 Supreme Court Antitrust Decision) Crossword Clue, Expresses Inspiring Thanks For Asian Dishes Crossword Clue, Demolition Letters And A Hint To 17 , 24 , 47 And 57 Across Crossword Clue, 2009 Beyonc Hit Containing The Lyric I Got My Angel Now Crossword Clue, Film Fx Used In Marvel Movies Crossword Clue, Cover Of Bible Tale Represented Saint Paul And John? It was last seen in British cryptic crossword. (a) The formula for horizontal distance of a projectile is given by $\Delta x=(v_0\,\cos \theta)\, t$, since we are asked to find the total distance from launching to striking point $(x=?,y=-200\,{\rm m})$, which is the range of projectile, so the total time of flight is required which is obtained as below \[\begin{aligned} y&=-\frac 12 g\,t^2 + (v_0 \sin \theta)\,t +y_0 \\ -200&=-\frac 12 (9.8)\,t^2 + (150\times\,\sin 37^\circ)\,t+0\\ &\Longrightarrow \ 4.8\,t^2-90\,t-200=0 \end{aligned}\] The solution to the quadratic equation $ax^2 + bx+c=0$ is given \[x=\frac{-b\pm\sqrt{b^2 - 4\,a\,c}}{2a}\] Using that, one can find the total time of flight as below \[\begin{aligned}t&=\frac{90\pm\sqrt{(90)^2-4\,(4.8)(-200)}}{2(4.8)}\\ &= t_1=20.757\,{\rm s} \\ &\text{and} \\ t_2&\approx-2\,{\rm s} \end{aligned}\] Because the projectile fired at $t=0$ so the time of strike can not be a negative value. Recall that the projectile range is determined by Crossword Clue, Firm Raised A Lot Of Money Locally, Back In Trade Event Crossword Clue, Not Very Cerebral Lib Dem Playing With Words, Briefly Crossword Clue, Damn Energy Guzzling Old Banger! These axes are perpendicular, so Ax = A cos and Ay = A sin are used. Thus, either first, find the initial velocity of $v_0$ and then its vertical component or use the data for maximum height. Projectile vomiting is the uncontrollable and forceful extreme of "throwing up." Bouts of nausea are more common as a symptom than many other maladies, but when they lead to uncontrollable (and quite unpleasant) bouts of . All the above formulas were based on the non-zero launch angle. An artillery projectile to be fired from a large-caliber gun barrel. $v_y=0$, the projectile is in the highest point of its parabolic trajectory, so using the following kinematics equation for displacement in the vertical direction we have \[\begin{aligned} v_y^2-v_{0y}^2 &=2(-g)\Delta y \\ v^2 - \left(v_0 \sin \theta \right)^2 &=2(-g)\Delta y \\ 0-(82\times \sin 63^\circ)^2 &=2(-9.8)H\\ \Rightarrow H&=272.3\,{\rm m} \end{aligned}\]if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[300,250],'physexams_com-large-leaderboard-2','ezslot_3',128,'0','0'])};__ez_fad_position('div-gpt-ad-physexams_com-large-leaderboard-2-0');if(typeof ez_ad_units != 'undefined'){ez_ad_units.push([[300,250],'physexams_com-large-leaderboard-2','ezslot_4',128,'0','1'])};__ez_fad_position('div-gpt-ad-physexams_com-large-leaderboard-2-0_1'); .large-leaderboard-2-multi-128{border:none !important;display:block !important;float:none !important;line-height:0px;margin-bottom:7px !important;margin-left:0px !important;margin-right:0px !important;margin-top:7px !important;max-width:100% !important;min-height:250px;padding:0;text-align:center !important;}. I'm not sure how to begin, so I made a chart of the X and Y motions If you get stuck with the word Large projectile used by the armies of the sea, don't worry - we have all the solutions right here! Airplanes, guided missiles, and rocket-propelled spacecraft are sometimes also said to follow a trajectory. where is the projectile located at the A: Motion of projectile can be divided into x component and y component Q: A golfer hits a golf ball on a flat, horizontal surface with an initial velocity of 67.7 m/s @ 45. The wide geographic range as well as the wide historic range of these things we call projectiles raises some problems for the typical student of physics. A hypervelocity gun located at sea level launches a projectile at a velocity of 5000 m/s at an angle of 40 relative to the horizontal. Options View as: Grid List Show. They seem like they reside more in the realm of celestialmechanics than terrestrialmechanics. To solve more problems, refer to projectile motion problems. Q.13. (I've seen this before) 'lake is found in sea' is the wordplay. Vertical motion is symmetrical - the distance and . (b) Initial and final points of the projectile are at the same level i.e. Today's crossword puzzle clue is a cryptic one: Projectile, originally lost, is in the sea. The Japanese coast guard confirmed the projectile had fallen into the Sea of Japan, also known as the East Sea, at 2:25 p.m. local time. (a) the distance at which the projectile hit the ground. An object ceases to be a projectile once any real effect is made to change its trajectory. Given these assumptions, the following steps are then used to analyze projectile motion: Step 1. (b) Determine the distance X of point P from the base of the vertical cliff. from the top of Mount Everest, which is located 8848 m above sea level, would the arrow's horizontal displacement be larger than 7.32 km? Assume that the arrow cannot be shot faster than 100.0 m/s, that there is no air resistance, and that the arrow lands at sea level. (a) \[\begin{aligned} \Delta y&=-\frac 12 gt^2 +\left(v_0 \sin \theta \right)t\\0&=-\frac 12 (9.8)t_T^2 +\left(82\times \sin 63^\circ\right)t_T \end{aligned}\] Thus, the total time that the cannon balls are in the air is $t_T=14.91\,{\rm s}$. Its goal is to provide a nice set of features operating on a project level without introducing external dependencies (when feasible). First, calculate the vertical and horizontal components of velocity and then use the Pythagorean theorem to find the resultant velocity vector as below Albion Head side-notched points have been classified within the Pacific Coast cluster. The motion of falling objects, as covered in Chapter 2.6 Problem-Solving Basics for One-Dimensional Kinematics, is a simple one-dimensional type of . b) What will be the maximum altitude of the projectile (km) ? (a) Deter- mine the time taken by the projectile to hit point P at ground level. Example (4): The 150 mm projectile weighed 35 kg and had a range of 6700 m, the 210 mm fired a 112 kg projectile 7800 m, and the 300 mm projectile weighed 125 kg with a range of 4500 yards. Dictionary Crossword Solver Quick Help We use historic puzzles to find the best matches for your question. Struggling to get that one last answer to a perplexing clue? a. Projectile Point Identification Guide. Any effects of the atmosphere can be neglected. Resolve or break the motion into horizontal and vertical components along the x- and y-axes. Where, $y$ and $x$ are the vertical and horizontal displacements, respectively. Then in the pattern box let us know how many . Such projectiles vary from 10:1 to 15:1 in length-to-diameter ratio. To experience a 1 shift in "down" would require traveling 1360 of the circumference of the Earth roughly 110km (70mi) or the length of a typical morning commute to work in Southern California. By assuming a constant value for the acceleration due to gravity, we make the problem easier to solve and (in many cases) do not really lose all that much in the way of accuracy. It also reduces direct impact damage from ghast fireballs and wither skulls, but not from their explosions. The projectile was reportedly fired towards the east sea. Notched Projectile Points of the. \[\begin{aligned} y&=-\frac 12 gt^2 + (v_0\,\sin \theta)\,t+y_0\\ -30&=-\frac 12 (9.8)\,t^2 + (10\times \sin 20^\circ)\,t+0\\ & \Rightarrow \,t_1=2.848\,{\rm s} \ , \ t_2=-2.15\,{\rm s} \end{aligned}\] Since the berry dropped at the initial time $t=0$, so the total time the berry is in the air (accepted time) is $t_1=2.848\,{\rm s}$. This case is called horizontal projectile motion and its formulas are as below $$\begin{aligned} v_{0x}&=v_0 \\ v_{0y}&=0\\ \Delta x&=v_0 \,t\\ \Delta y&=-\frac 12 g\,t^2\\v_x&=v_{0x}\\ v_y&=-gt\\ v^{2} &= -2\,g\,\Delta y \end{aligned}$$ See Example (3) below. Thus for projectiles that won't rise higher than an airplane nor travel farther than the diameter of L.A., gravity is effectively constant. The South Korean Joint Chiefs of Staff said the projectile was fired toward North Korea's eastern sea from an inland area at 6:40 a.m. local time, but did not specify if the projectile was a . So put your thinking cap on and get ready for some fun! The maximum height of the projectile is given by the formula: H = v 0 2 s i n 2 2 g. The crossword solver is simple to use. The normal amounts of drag and buoyancy just aren't large enough to save the passengers on a doomed flight from an unfortunate end. It can find the time of flight, but also the components of velocity, the range of the projectile, and the maximum height of flight.Continue reading if you want to understand what is projectile motion, get familiar with the projectile motion definition, and determine the abovementioned values . For instance - finding project files has a portable implementation written in pure Emacs Lisp without the use of GNU find (but for performance sake . Since the projectile hit the ground below the considered origin so its coordinate is $(x=?,y=-200\,{\rm m})$. The Crossword Solver finds answers to classic crosswords and cryptic crossword puzzles. SEOUL, South Korea North Korea fired at least one unidentified projectile toward its eastern sea on Saturday, South Korea's military said, in its second launch this . If you discover one of these, please send it to us, and we'll add it to our database of clues and answers, so others can benefit from your research. Synopsis. How can I find a solution for Projectile, Large, Is Located In Sea? The longest shot on a golf tournament was made by Mike Austin in 1974. At some speed our hypothetical projectile would make it a quarter of the way around the Earth and then half way around and then eventually all the way around. Calculate the vertical distance, h, if the projectile's total time of flight is 4.5 seconds. When a projectile is sent on a very long journey, as is the case with ICBMs, the magnitude and direction of the acceleration due to gravity changes. With crossword-solver.io you will find 1 solutions. Seoul confirmed that their neighboring country South Korea has launched what appears to be the sixth projectile this year. By The Associated Press. Early Archaic. My problem isn't getting the different collision aspects, it's getting the projectile's location. We have 1 possible answer in our database. Projectile Protection reduces damage from arrows, thrown tridents, shulker bullets, llama spit, and blaze fireballs. b) What will be the maximum altitude of the projectile (km)? m/s 6 Every projectile problem is essentially two one-dimensional motion problems. The time between throwing to landing points is called total flight time $T$ and is obtained by $\Delta y=-\frac 12\,g\,t^2$. Such distinctions are arbitrary, however, as there is only one mechanics. The ground at the top of the cliff is level, with a constant elevation of 25.0 m above the cannon. To find extrema for D we set The Crossword Solver found 20 answers to "projectile large is located in sea", 9 letters crossword clue. Since said that the stone is thrown horizontally, so $\theta=0$. Adding this value with the cliff height, the total height the projectile reaches from the ground is obtained. Here are the possible solutions for "Projectile, large, is located in sea" clue. A projectile is any object that is cast, fired, flung, heaved, hurled, pitched, tossed, or thrown. You can easily improve your search by specifying the number of letters in the answer. \[\begin{aligned}\Delta y &=-\frac 12 gt^2 +\underbrace{v_0 \sin \theta}_{v_{0y}} t\\ 0&=-\frac 12 (9.8)t_T^2 +(6.87) t_T\end{aligned}\] Thus, the time of flight is $t_T=1.40\,{\rm s}$. However that SHOULD NOT be the case since the projectile must move and update it's location in order to 'hit' the other player. Sort By Republic Fleet Carbonized Lead L (projectile ammo) 100,000 units. (b) the maximum height above the ground reached by the projectile. Large projectile used by the armies of the sea 'sea' becomes 'baltic' (Baltic is an example**). These forms have relatively large lanceolate (lance-shaped) points with nearly parallel sides, slightly concave bases, and single or multiple basal flake scars, or flutes, that rarely extend more than a third of the way up the body. A soccer ball is kicked at $35^\circ$ above the horizontal, it lands $13.8\,{\rm m}$ away and reaches a maximum height of $2.42\,{\rm m}$. hotels Projectile, originally lost, is in the sea student is included in sea projectile Sea where the Greek island of Santorini is located Substituting it into the projectile formula for vertical displacement, we have \[\begin{aligned} y&=-\frac 12 gt^2 + (v_0\,\sin \theta)\,t+y_0 \\ h&=-\frac 12 (9.8)(9.2)^2 + (150\times \sin 37^\circ)(9.2)+0\\ h&=415.76\,{\rm m} \end{aligned}\] In the second line, $y_0$ is set to zero since from the beginning of problem we adopted the origin of the coordinate $(x_0=0,y_0=0)$ at the firing point.



March Madness Network Crossword Clue, Slake 6 Letters Crossword, Westport, Massachusetts, Golf Course Crossword Clue, Tufts Admitted Student Network,